How do you graph the line #Y=3x-4 #?
1 Answer
Jul 19, 2018
See a solution process below:
Explanation:
First, solve for two points which solve the equation and plot these points:
First Point: For
Second Point: For
We can next plot the two points on the coordinate plane:
graph{(x^2+(y+4)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}
Now, we can draw a straight line through the two points to graph the line:
graph{(y-3x+4)(x^2+(y+4)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}