How do you graph the line $Y = 3 x - 4$ $Y=3x-4$ ?

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Answer 1 · 2018-07-19T16:13:28

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (3 \cdot 0) - 4$ $y = (3 * 0) - 4$

$y = 0 - 4$ $y = 0 - 4$

$y = - 4$ $y = -4$ or $(0, - 4)$ $(0, -4)$

Second Point: For $y = 2$ $y = 2$

$y = (3 \cdot 2) - 4$ $y = (3 * 2) - 4$

$y = 6 - 4$ $y = 6 - 4$

$y = 2$ $y = 2$ or $(2, 2)$ $(2, 2)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+4)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y-3x+4)(x^2+(y+4)^2-0.04)((x-2)^2+(y-2)^2-0.04)=0 [-10, 10, -5, 5]}

How do you graph the line Y=3x-4 Y=3x−4Y=3x-4 ?