How do you graph the system $y > - 2 x + 3$ $y > -2x + 3$ and $y < 4 x - 1$ $y < 4x - 1$ ?

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Answer 1 · 2015-06-07T18:18:04

(1) y > -2x + 3

(2) y < 4x - 1

First, graph the Line 1: y1 = -2x + 3. The solution set of the inequality (1) is the area above the Line 1. Color this area

Next, graph the Line 2: y2 = 4x - 1. The solution set of the inequality (2) is the area below this line y2. Color it.

The combined solution set of the system is the commonly shared area.

How do you graph the system y > -2x + 3y>−2x+3y > -2x + 3 and y < 4x - 1y<4x−1y < 4x - 1?