How do you graph $θ = 30^{\circ}$ $\theta = 30^\circ$ ?

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Answer 1 · 2018-07-25T15:53:23

$θ = α$ $theta = alpha$ is the equation of the radial line,from pole, in that

direction.

The radial line is in $[Q_{1} Q_{2} Q_{3} Q_{4}]$ $[ Q_1 Q_2 Q_3 Q_4 ]$ ,

if $α \in [Q_{1} Q_{2} Q_{3} Q_{4}]$ $alpha in [ Q_1 Q_2 Q_3 Q_4 ]$ , respectively.

Here, it is in $Q_{1}$ $Q_1$ , wherein both $x and y \geq 0$ $x and y >= 0$ .

The slope of this line is $tan (30^{o}) = \frac{1}{\sqrt{3}}$ $tan ( 30^o ) = 1/sqrt3$ and the Cartesian

equation is

$y = \frac{1}{\sqrt{3}} x, x \geq 0 and y \geq 0$ $y =1/sqrt3 x, x >=0 and y >= 0$ , See graph.
graph{y-x/sqrt3 =0[0 20 0 10]}

How do you graph θ=30∘\theta = 30^\circ?