How do you graph $(x-1)^2+(y-4)^2=9$ ?

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Answer 1 · 2015-07-08T02:05:25

You find the centre, the vertices, and the endpoints of the function. Then you plot the graph.

$(x-1)^2 + (y-4)^2 = 9$

This is the standard form for the equation of a circle with centre at ( $1,4$ ) and radius $sqrt9 = 3$ .

This means that, to find the vertices, you go 3 units up from the centre and 3 units down.

Thus, the vertices are at ( $1,7$ ) and ( $1,1$ ).

To find the endpoints, you go 3 units left of the centre and 3 to the right.

Thus, the endpoints are at ( $-2,4$ ) and ( $4,4$ ).

Plot these points on a graph.

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Now draw a smooth circle through these four points.

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And you have your graph.

How do you graph (x-1)^2+(y-4)^2=9(x-1)^2+(y-4)^2=9?