How do you graph $x - \frac{2}{3} y = 1$ $x - 2/3y = 1$ by plotting points?

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Answer 1 · 2017-09-04T16:23:20

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point:

For $y = 0$ $y = 0$

$x - (\frac{2}{3} \cdot 0) = 1$ $x - (2/3 * 0) = 1$

$x - 0 = 1$ $x - 0 = 1$

$x = 1$ $x = 1$ or $(1, 0)$ $(1, 0)$

Second Point:

For $y = 3$ $y = 3$

$x - (\frac{2}{3} \cdot 3) = 1$ $x - (2/3 * 3) = 1$

$x - 2 = 1$ $x - 2 = 1$

$x - 2 + 2 = 1 + 2$ $x - 2 + color(red)(2) = 1 + color(red)(2)$

$x - 0 = 3$ $x - 0 = 3$

$x = 3$ $x = 3$ or $(3, 3)$ $(3, 3)$

We can next graph the two points on the coordinate plane:

graph{((x-1)^2+y^2-0.035)((x-3)^2+(y-3)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x-2/3y-1)((x-1)^2+y^2-0.035)((x-3)^2+(y-3)^2-0.035)=0 [-10, 10, -5, 5]}

How do you graph x−23y=1x - 2/3y = 1 by plotting points?