How do you graph $x^2+y^2=16$ ?

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Answer 1 · 2016-01-30T01:58:40

This is simply a circle of radius $4$ , centered at the origin $(0, 0)$ .

The standard form for the equation of a circle is:

$(x-a)^2 + (y-b)^2 = c^2$

where the center of the circle is the point $(a, b)$ and its radius is $c$ units.

In this case $a$ and $b$ are both $0$ , and $4^2=16$ .

How do you graph x^2+y^2=16x^2+y^2=16?