How do you graph #x/2 - y = 7#?
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Refer to the explanation.
Solve for #y# to change the equation to slope-intercept form:
#y=mx+b#,
where:
#m# is the slope and #b# is the y-intercept, which is the value for #y# when #x=0#.
Given:
#x/2-y=7#
Subtract #x/2# from both sides.
#-y=-x/2+7#
Multiply both sides by #-1#. This will reverse the signs.
#y=x/2-7#
#y=1/2x-7#
#m=1/2#
#b=-7#
Determine two points, such as the y-intercept and x-intercept (value of #x# when #y=0#).
Y-intercept: #(0,-7)#
X-intercept: #(14,0)# See below for the calculations.
#0=1/2x-7#
Add #7# to both sides.
#7=1/2x#
Divide both sides by #1/2#. When dividing by a fraction, invert the fraction and multiply.
#7/(1/2)=x#
#7xx2/1=x#
#14=x#
Plot the x- and y-intercepts. Draw a straight line through the points.
graph{y=1/2x-7 [-9.34, 10.66, -8.84, 1.16]}
