Question

How do you graph `(x-3)^3 + (y+2)^2 = 4` on a coordinate graph?

Answer 1

Refer to explanation

Explanation:

This is a circle .The general formula is

`(x-x_o)^2+(y-y_o)^2=R^2` where `(x_o,y_o)` is the cirlce centre
and R is the radius.

In our case the centre of circle is `(3,-2)` and the radius is R=2

Hence the graph is graph{(x-3)^2+(y+2)^2=4 [-8.89, 8.885, -4.444, 4.44]}