How do you graph $x = (\frac{5}{2}) y^{2}$ $x = (5/2)y^2$ ?

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Answer 1 · 2017-10-26T11:43:39

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This is a quadratic in $y$ $y$ instead of in $x$ $x$ . Thus the axis of symmetry is parallel to the y-axis.

As the $y^{2}$ $y^2$ term is positive the general form of the graph is $\subset$ $sub$ . Negative would give $\supset$ $sup$

As there is no constant or $y$ $y$ term the graphs axis of symmetry is the x-axis and the vertex is at $(x, y) = (0, 0)$ $(x,y)=(0,0)$

The coefficient of $y^{2}$ $y^2$ is greater than one so it has the effect of widening (vertically) the $x = y^{2}$ $x=y^2$

Tony B

How do you graph x=(52)y2x = (5/2)y^2?