How do you graph ${(x + 5)}^{2} + {(y - 2)}^{2} = 49$ $(x + 5)^2 + (y - 2)^2 = 49$ ?

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Answer 1 · 2016-01-19T12:53:39

This is the general equation of a circle centred at $(- 5, 2)$ $(-5,2)$ and having radius $7$ $7$ .

Any circle centred at $(a, b)$ $(a,b)$ and with radius $r$ $r$ has general equation ${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ $(x-a)^2+(y-b)^2=r^2$ .

Therefore this is the general equation of a circle centred at $(- 5, 2)$ $(-5,2)$ and having radius $7$ $7$ .

The graph will be the union of the following 2 semi-circles :

graph{2+sqrt((49-(x+5)^2) [-20.27, 20.27, -10.14, 10.12]}

graph{2-sqrt((49-(x+5)^2) [-20.27, 20.27, -10.14, 10.12]}

and it should look like this

graph{x^2 +10x + y^2 - 4y - 20 = 0 [-20.27, 20.27, -10.14, 10.12]}

How do you graph (x + 5)^2 + (y - 2)^2 = 49(x+5)2+(y−2)2=49(x + 5)^2 + (y - 2)^2 = 49?