How do you graph $x=(y+4)^2-2$ ?

Question

1258 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-28T09:06:06

See below

$x=(y+4)^2-2$

We need to isolate $y$

$(y+4)^2 =x+2$

$y+4 = +-sqrt(x+2)$

$y = +-sqrt(x+2)-4$

We can now graph $y$ as below:

graph{((sqrt(x+2)-4)-y)((-sqrt(x+2)-4)-y)=0 [-12.4, 28.13, -11.59, 8.69]}

How do you graph x=(y+4)^2-2x=(y+4)^2-2?