How do you graph $y=0.1tan((pix)/4+pi/4)$ and include two full periods?

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Answer 1 · 2018-07-04T04:16:49

Period is 4 radian. See graph and explanation.

The period of tan ( ax + b ) ia $pi/abs(a)$ . So,

the period here is $pi/(pi/4) = 4$ radian.

Graph for two periods, $x in ( -3, 5 )$ , with asymptotes x + 3 =

0, $x - 1 = 0$ and $x - 5 = 0$ :

graph{(y-0.1tan(pi/4(x+1)))(x+3+.02y)(x-1+.02y)(x-5+.02y)=0[-3 5 -2 2]}

How do you graph y=0.1tan((pix)/4+pi/4)y=0.1tan((pix)/4+pi/4) and include two full periods?