How do you graph $y=1/2sin2x$ ?

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Answer 1 · 2018-03-18T11:00:20

As below.

standard form of equation is $y = a sin(bx -c) + d$

Given : $y = (1/2) sin 2x$

$" Amplitude " = a = 1/2$

$"Period " = P = (2pi) / |b| = (2pi) / 2 = pi$

$Phase Shift" = -c / b = 0, "Vertical Shift " = d = 0$

graph{(1/2) sin (2x) [-10, 10, -5, 5]}

How do you graph y=1/2sin2xy=1/2sin2x?