How do you graph $y = - \frac{1}{2} x^{2}$ $y = -1/2x^2$ ?

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How do you graph $y = - \frac{1}{2} x^{2}$ $y = -1/2x^2$ ?

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Answer 1 · 2017-10-07T17:15:14

$y = - (\frac{x^{2}}{2})$ $y=-(x^2/2)$
graph{-(x^2/2) [-10, 10, -5, 5]}

Explanation:

$y = - (\frac{x^{2}}{2})$ $y=-(x^2/2)$
$x = 0, y = 0$ $x=0,y=0$
$x = 1, y = - (\frac{1}{2})$ $x=1,y=-(1/2)$
$x = - 1, y = - (\frac{1}{2})$ $x=-1,y=-(1/2)$
$x = 2, y = - 2$ $x=2,y=-2$
$x = - 2, y = - 2$ $x=-2,y=-2$
Now we can plot in the graph with values of these five points.

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How do you graph $y = - \frac{1}{2} x^{2}$ $y = -1/2x^2$ ?

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How do you graph $y = - \frac{1}{2} x^{2}$ $y = -1/2x^2$ ?