How do you graph $y=1/4cos3x$ ?

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Answer 1 · 2018-05-10T02:29:04

As detailed

$y = A cos (Bx - C) + D$

Given $y = (1/4) cos x$

$A = 1/4, B = 3, C = 0, D = 0$

$Amplitude = |A| = 1/4$

$"Period " = (2pi) / |B| = (2pi)/3$

$"Phase Shift " = -C / B = 0$

$"Vertical Shift ' = D = 0$

graph{(1/4)cos(3x) [-10, 10, -5, 5]}

How do you graph y=1/4cos3xy=1/4cos3x?