How do you graph $y = 1 - cos(pix)$ ?

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Answer 1 · 2018-08-07T14:21:02

As below.

$y = 1 - cos (pi x)$

$y = A cos (Bx - C) + D$ is the standard form of cosine function.

$A = -1, B = pi, C = 0, D = 1$

$Amplitude = |A| = |-1| = 1$

Period $= (2pi) / |B| = (2pi) / |pi| = 2$

Phase Shift $= -C / B = 0$

Vertical Shift $= D = 1$

graph{- cos(pi x) + 1 [-10, 10, -5, 5]}

How do you graph y = 1 - cos(pix)y = 1 - cos(pix)?