How do you graph $y=10sin2x$ ?

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Answer 1 · 2018-07-13T01:44:11

As below.

Standard form of a sine function is $y = A sin (Bx - C) + D$

$"Given : " y = 10 sin (2x)$

$A = 10, B = 2, C = D = 0$

$Amplitude = |A| = 10$

$"Period " = (2pi)/ |B| = (2pi) / 2 = pi$

$"Phase Shift " = -C / B = 0$

$"Vertical Shift " = D = 0$

graph{10 sin (2x) [-10, 10, -5, 5]}

How do you graph y=10sin2xy=10sin2x?