How do you graph y= 12+2xy=12+2x using intercepts?

1 Answer
Jan 28, 2016

Try this:

Explanation:

We start from the x-"intercept"xintercept by setting y=0y=0, so we get:
0=12+2x0=12+2x
x=-12/2=-6x=122=6
so:
x-xintercept at: (-6,0)(6,0)

Then we find the y-"intercept"yintercept by setting x=0x=0, so we get:
y=12y=12
so:
y-yintercept at: (0,12)(0,12)

Graphically:
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