How do you graph #y = 2 + 1/2csc(x - 3pi/4)#?

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Answer 1 · 2018-03-31T10:07:39

As below.

Standard form of equation : #y = A csc(Bx - C) + D#

Given equation is #y = (1/2) csc(x - ((3pi)/4)) + 2#

#Amplitude = A = 1/2 = " None for csc function"#

#"Period " = (2pi) / |B| = 2pi#

#"Phase Shift " = -C / B = (3pi)/4, " " (3pi)/4 " to the right"#

#"Vertical Shift " = D = 2#

graph{(1/2) csc (x - (3pi)/4) + 2 [-10, 10, -5, 5]}