Question

How do you graph `y=-2+8x`?

Answer 1

`x` intercept is `(1/4,0)`

`y` intercept is `(0,-2)`

slope is `8`

Explanation:

We need a few pieces of information to be able to graph a function. We need the `x` and `y` intercepts and the slope.

We can use slope-intercept form to help us find two of these components. Slope-line form is `y=mx+b`, where `m` is slope and `b` is the `y` intercept.

In our case, `m` is `8`, so our slope is `8`, and our `y` intercept is `-2`.

So, we have our slope and `y` intercept, but we still need our `x` intercept. To find that, we set `y` to `0` and solve for `x`:

`0=-2+8x`

add `2` to both sides

`2=8x`

divide by `8`

`1/4=x`

So, our `x` intercept is `(1/4,0)`, our `y` intercept is `(0,-2)`, and our slope is `8`, or up `8`, over `1`

The final graph should look like this:
graph{y=-2+8x}