Question

How do you graph `y = -2 sin 2x`?

Answer 1

For any general sinusoidal trigonometric equation of form `y=asinbx`, a is the amplitude which represents the maximum displacement from the x axis, and `(2pi)/b` is the period which represents the amount of radians required for a full cycle of the graph.

So in this case, a=-2, period = `(2pi)/2=pi rad`
This means that the graph has maximum displacement 2 and completes a full cycle in `pi` rad.

Hence the graph will look as follows :

graph{-2sin(2x) [-4.933, 4.93, -2.466, 2.466]}