How do you graph $y= 2 sin 3(θ + π/4)$ ?

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Answer 1 · 2018-07-04T02:07:39

As Below.

Sine function format is $y = A sin( Bx - C) + D$

$y = 2 sin (3theta - (3pi)/4)$

$A = 2, B = 3, C = (3pi)/4, D = 0$

$Amplitude = |A| = 2$

$"Period " = (2pi) / |B| = (2pi)/3$

$"Phase Shift " = -C / B = -((3pi)/4)/3 = -pi/4, color(crimson)(pi/4" to the LEFT"$

$"Vertical Shift " = D = 0$

graph{2 sin(3x + (3pi)/4) [-10, 10, -5, 5]}

How do you graph y= 2 sin 3(θ + π/4)y= 2 sin 3(θ + π/4)?