How do you graph #y=-2sec((pix)/4-pi/2)#?

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Answer 1 · 2018-06-18T01:43:46

As below.

Standard form of secant function is #y = A sec (Bx - C) + D#

#"Given : " y = -2 sec((pi/4)x - (pi/2))#

#A = -2, B = pi/4, C = pi/2, D = 0#

#"Amplitude " = |A| = |-2| = 2#

#"Period " = (2pi) / |B| = (2pi) / (pi/4) = 8#

#"Phase Shift " = -C / B = (-pi/2) / (pi/4) = 2#

#"Vertical Shift " = D = 0#

graph{-2 sec((pi/4)x - (pi/2)) [-10, 10, -5, 5]}