How do you graph $y=2sin(x-pi/2)+3$ ?

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Answer 1 · 2018-06-26T06:18:52

As below.

$"standrad form of sine function is " y = A sin (Bx - C) + D$

$"Given ' y = 2 sin (x - pi/20 + 3$

$A = 2, B = 1, C = pi/2, D = 3$

$"Amplitude ' = |A| = 2$

$"Period ' = (2pi) / |B| = 2pi$

$"Phase Shift " = -C / B = -(pi/2) / 1 = -pi/2, " " color(crimson)(pi/2 " to the LEFT"$

$"Vertical Shift " = D = 3$

graph{2 sin(x - pi/2) + 3 [-10, 10, -5, 5]}

How do you graph y=2sin(x-pi/2)+3y=2sin(x-pi/2)+3?