How do you graph y=2sin(x+π)?

1 Answer
Apr 15, 2016

Please see below.

Explanation:

A typical graph of y=sinx has domain for all values of x and range is from [1,1].

It is a cyclical curve and repeats after every 2π, hence its period is 2π.

It's value is 0 at each nπ, it touches a maximum value of 1 at each 2nπ+π2 and a minimum value of 1 at each 2nππ2 (where n is an integer).

It appears like graph{sin(x) [-10, 10, -2, 2]}

If we draw the graph of y=2sin(x+π), the range will be doubled due to multiplier 2 and will be [2,2].

However, the graph will be shifted by π and hence minimum value will be 2 at each 2nπ+π2 and a maximum value of 2 at each 2nππ2 (where n is an integer). But the function will continue to have value 0 at each nπ.

As the period of curve is 2π, it does not matter whether you say it has shifted by π to the left or right.

The graph of 2sin(x+π) appears like graph{2sin(x+pi) [-10, 10, -2, 2]}