How do you graph $y=-2sin3x$ ?

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Answer 1 · 2016-04-26T16:15:23

y is periodic, with period $( 2 pi)/3$ ..

In $[0, (2 pi)/3]$ , the graph is one full wave, with amplitude 2..

The lowest point is $(pi/6, -2)$ . The crest is at $(pi/2, 2).$ .

$(pi/3, 0)$ on the x-axis bisects this wave..
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#The graph for y=+2 sin (3 x) will be the mirror image of this graph, with respect to x-axis

How do you graph y=-2sin3x y=-2sin3x?