How do you graph $y = 2 sin π x$ $y=2sinpix$ ?

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Answer 1 · 2018-07-26T05:17:08

See graph and details.

$y = 2 sin π x \in 2 [- 1, 1] = [- 2, 2]$ $y = 2 sin pix in 2 [- 1, 1 ] = [ -2, 2 ]$

Period = ( 2pi )/pi = 2.

Amplitude = 2.

See graph depicting these aspects.:
graph{(y -2 sin (pi x ))(y^2-4)(x^2-1)=0}[-6 6 -3 3]

Graph for precisely one half.period, $x \in [- \frac{1}{2}, \frac{1}{2}]$ $x in [ - 1/2, 1/2 ]$ , using the

inverse $x - \frac{1}{π} arcsin (\frac{y}{2}) = 0$ $x-1/pi arcsin(y/2)=0$ that does the truncation:
graph{x-1/pi arcsin(y/2)=0[-1/2 1/2 -2 2] }

How do you graph y=2sinπxy=2sinpix?