How do you graph #y=-2sinx+1#?

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Answer 1 · 2018-05-10T02:09:29

As below.

#"Standard form of equation for a sine function is "#

#y = A sin (Bx - C) + D#

#"Given equation is " y = - 2 sin x + 1#

#A = -2, B = 1, C = 0, D = 1#

#Amplitude = |A| = 2#

#"Period " = P = (2pi) / |B| = 2pi#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift " = D = +1#

graph{-2 sin x + 1 [-10, 10, -5, 5]}