How do you graph $y=-2sinx+1$ ?

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Answer 1 · 2018-05-10T02:09:29

As below.

$"Standard form of equation for a sine function is "$

$y = A sin (Bx - C) + D$

$"Given equation is " y = - 2 sin x + 1$

$A = -2, B = 1, C = 0, D = 1$

$Amplitude = |A| = 2$

$"Period " = P = (2pi) / |B| = 2pi$

$"Phase Shift " = -C / B = 0$

$"Vertical Shift " = D = +1$

graph{-2 sin x + 1 [-10, 10, -5, 5]}

How do you graph y=-2sinx+1y=-2sinx+1?