How do you graph $y - (- 3) = - \frac{1}{2} (x - (0))$ $y-(-3)=-1/2(x-(0))$ ?

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Answer 1 · 2017-10-26T11:56:47

See a solution process below:

First, clean up the signs and parenthesis in the equation to simplify it. Remember, minus a minus is a plus;

$y + 3 = - \frac{1}{2} (x - 0)$ $y + 3 = -1/2(x - 0)$

$y + 3 = - \frac{1}{2} x$ $y + 3 = -1/2x$

$y + 3 - 3 = - \frac{1}{2} x - 3$ $y + 3 - color(red)(3) = -1/2x - color(red)(3)$

$y + 0 = - \frac{1}{2} x - 3$ $y + 0 = -1/2x - 3$

$y = - \frac{1}{2} x - 3$ $y = -1/2x - 3$

Next, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (- \frac{1}{2} \cdot 0) - 3$ $y = (-1/2 * 0) - 3$

$y = 0 - 3$ $y = 0 - 3$

$y = - 3$ $y = -3$ or $(0, - 3)$ $(0, -3)$

Second Point: For $x = 2$ $x = 2$

$y = (- \frac{1}{2} \cdot 2) - 3$ $y = (-1/2 * 2) - 3$

$y = - 1 - 3$ $y = -1 - 3$

$y = - 4$ $y = -4$ or $(2, - 4)$ $(2, -4)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y+3)^2-0.075)((x-2)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y + (1/2)x+3)(x^2+(y+3)^2-0.075)((x-2)^2+(y+4)^2-0.075)=0 [-15, 15, -7.5, 7.5]}

How do you graph y-(-3)=-1/2(x-(0))y−(−3)=−12(x−(0))y-(-3)=-1/2(x-(0))?