How do you graph $y = 3 + 4 sin (pi/2) (x-2)$ ?

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Answer 1 · 2015-11-14T16:18:17

First, distribute the $pi/2$

$y=4sin[(pi/2)x-pi]+3$

phase shift : The $-pi$ results in a phase shift to the right $pi$ units

period : The coefficient ( $pi/2$ ) in front of x determines the period ...
$=(2pi)/(pi/2)=4$

vertical shift: 3 units up

amplitude $=4$

hope that helped

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How do you graph y = 3 + 4 sin (pi/2) (x-2)y = 3 + 4 sin (pi/2) (x-2)?