Question

How do you graph `y = (-3/4) x^2`?

Answer 1

See explanation

Explanation:

The coefficient of `x^2` is negative so the general shape of the graph is `nn`

As the coefficient is less than 1 it has the effect of widening the 'base graph' of `y=x^2`
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Write as: `y=-3/4x^2+0x+0`

Compare to the standardised equivalent of:

`y=ax^2+bx+c`

The y-intercept `->c=0`

The x-intercept is at `y=0` giving `0=-3/4x^2 => x=0`

As there is only 1 solution (`x=0`) the x-axis is tangential to the vertex. Also, as this is at `y=0` we have:

Vertex`->(x,y)=(0.0)`

Other than this and you will to build a table of values. Plot the points and draw the best plot you can that passes through those points.