How do you graph $y=3-cosx$ ?

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Answer 1 · 2018-03-07T14:27:22

As below.

Standard form of equation $y = a cos (bx + c) + d$

$y = -cos x + 3$

Amplitude $= a = 1$

Period $= (2pi) / |b| = 2 pi$

Phase shift $= c / b = 0$ to the right

Vertical shift $= d = 3$

graph{-cos (x) + 3 [-10, 10, -5, 5]}

How do you graph y=3-cosx y=3-cosx?