How do you graph $y =3 sin (x +(2pi)/3)$ ?

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Answer 1 · 2018-03-19T05:39:13

As Below.

$y = 3 sin (x + (2pi)/3)$

Standard form $y = A sin (Bx - C) + D$

$Amplitude = |A| = 3$

Period $= P = (2pi) / |B| = (2pi) / 1 = 2pi$

$"Phase Shift " = (-C) / B = -((2pi)/3) color(white)(aaa)$ $((2pi)/3 "to the left")$

$"Vertical Shift " = D = 0$

graph{3 sin (x + (2pi)/3) [-10, 10, -5, 5]}

How do you graph y =3 sin (x +(2pi)/3)y =3 sin (x +(2pi)/3)?