How do you graph $y = 3cos(-2x + pi/2)$ ?

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Answer 1 · 2018-06-07T06:48:21

As below.

$y = A cos (Bx - C) + D$ is the standard form

$y = 3 cos (-2x + pi/2)$

$A = 3, B = -2, C = pi/2, D = 0$

$Amplitude = |A| = 3$

$"Period " = (2pi)/|B| = (2pi) / 2 = pi$

$"Phase Shift " = -C / B = -(pi/2) / -2 = pi/4$ , $color(red)(pi/4 " to the right"$

$"Vertical Shift " = 0$

graph{3 cos(pi/2 - 2x) [-10, 10, -5, 5]}

How do you graph y = 3cos(-2x + pi/2)y = 3cos(-2x + pi/2)?