Question

How do you graph `y = 3sin(2x - pi/2) + 1`?

Answer 1

As below.

Explanation:

Standard form of sinusoidal wave equation is

`color(crimson)(y = A sin (Bx - C) + D`

Given `y = 3 sin (2x - (pi/2)) + 1`

`Amplitude = |A| = 3`

`"Period " = (2pi) / |B| = (2pi) / 2 = pi`

`"Phase Shift " = -C / B = (pi/2) / 2 = pi/4 " to the right"`

`"Vertical Shift " = D = 1`

graph{3 sin(2x - (pi/2)) + 1 [-10, 10, -5, 5]}