Question

How do you graph `y=3x^2+1` and its inverse?

Answer 1

By finding plotting points

Explanation:

If your x is 0, your function `y=1`
If your x is 1, your function `y=4`
If your x is 2, your function `y=13` etc.

Here is the graph:
graph{(3x^2)+1 [-4, 4, -3, 25]}

Your inverse function is basically

`f(x)=1/(3x^2+1)`
You can graph using the same method detailed above.
Here is graph of inverse function.

graph{1/((3x^2)+1) [-4, 4, -1, 2]}