Question

How do you graph `y < 3x+5` and `y> -3x +2`?

Answer 1

Graph and solve the system:
(1) y < 3x + 5
(2) y > -3x + 2

Explanation:

First, graph Line y1 = 3x + 5 by its 2 intercepts.
Make x = 0 --> y = 5. Make y = 0 --> x = -5/3>
The solution set of inequality (1) is the area below the line y1. Color or shade it.
Next, graph the line y2 = - 3x + 2 by its 2 intercepts.
The solution set of the inequality (2) is the area above the Line y2. Color or shade it.
The compound solution set is the commonly shared area.

graph{3x + 5 [-10, 10, -5, 5]}
graph{-3x + 2 [-10, 10, -5, 5]}