How do you graph $y = 4 + \frac{2}{3} x$ $y=4+2/3x$ on a coordinate grid?

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Answer 1 · 2018-06-16T11:53:57

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = 4 + (\frac{2}{3} \cdot 0)$ $y = 4 + (2/3 * 0)$

$y = 4 + 0$ $y = 4 + 0$

$y = 4$ $y = 4$ or $(0, 4)$ $(0, 4)$

Second Point: For $x = 3$ $x = 3$

$y = 4 + (\frac{2}{3} \cdot 3)$ $y = 4 + (2/3 * 3)$

$y = 4 + \frac{6}{3}$ $y = 4 + 6/3$

$y = 4 + 2$ $y = 4 + 2$

$y = 6$ $y = 6$ or $(3, 6)$ $(3, 6)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-4)^2-0.1)((x-3)^2+(y-6)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y - 4 - (2/3)x)(x^2+(y-4)^2-0.1)((x-3)^2+(y-6)^2-0.1)=0 [-20, 20, -10, 10]}

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