How do you graph #y> -4-x# on the coordinate plane?
2 Answers
See a solution process below:
Explanation:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
For:
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
graph{(x^2+(y+4)^2-0.125)((x+4)^2+y^2-0.125)(y+x+4)=0 [-20, 20, -10, 10]}
We can now change the boundary line to a dashed line because the inequality operator does not contain an "or equal to" clause. And, we can shade the right side of the line.
graph{(y+x+4) > 0 [-20, 20, -10, 10]}
See below.
Explanation:
First graph the line
With line plotted, check a set of coordinates above and below the line to see which satisfy the inequality.
graph{y=-x-1 [-10, 10, -5, 5]}
Above the line:
Area above the line is the included region. Shade this region.
graph{y > -4-x [-41.1, 41.07, -20.55, 20.55]}