How do you graph y=-4cos(1/2x-pi)+3y=4cos(12xπ)+3?

1 Answer
Feb 12, 2018

There are four main components in graphing this function:

Explanation:

  • Amplitude - twice the yy distance from maximum to minimum
  • Period - the xx distance between a repetition of the values
  • Horizontal Phase Shift - the shift on the xx axis
  • Vertical Phase Shift - the shift on the yy axis

In the function a*cos(bx+c)+dacos(bx+c)+d

  • Amplitude = aa
  • Period = (2pi)/b2πb
  • Horizontal Phase Shift = c/bcb
  • Vertical Phase Shift = dd

Thus you can figure out:

  • Amplitude = 44
  • Period = piπ
  • Horizontal Phase Shift = -pi/2π2
  • Vertical Phase Shift = 33

Note:

The amplitude is always positive because distances can not be negative. When the aa term is negative there is a flip over the xx axis

When you graph this function you will get:
graph{-4*cos(1/2x-pi)+3 [-9.46, 10.54, -1.76, 8.24]}