Question

How do you graph `y=4cot(1/3t)` over the interval `[-3pi, 3pi]`?

Answer 1

Using a graphing calculator:
Change the function to `tan`: `y = 4/(tan(1/3t))`

Explanation:

`cot theta = 1/(tan theta)`

Using a graphing calculator:
Change the function to `tan`: `y = 4/(tan(1/3t))`

Make sure your MODE = radians.
Change your WINDOW to Xmin = `-3pi`, Xmax = `3pi`

There are holes at `(-3pi)/2` and `(3pi)/2`

There are vertical asymptotes at `x = 0` and `x = -3pi`

graph{4/tan(x/3) [-10, 10, -5, 5]}