How do you graph #y=(7x)/(-x-15)# using asymptotes, intercepts, end behavior?
1 Answer
see explanation.
Explanation:
The denominator of y cannot be zero as this would make y undefined. Equating the denominator to zero and solving gives the value that x cannot be and if the numerator is non-zero for this value then it is a vertical asymptote.
solve :
#-x-15=0rArrx=-15" is the asymptote"# Horizontal asymptotes occur as
#lim_(xto+-oo),ytoc" (a constant)"# divide terms on numerator/denominator by x
#y=((7x)/x)/(-x/x-15/x)=7/(-1-15/x)# as
#xto+-oo,yto7/(-1-0)#
#rArry=-7" is the asymptote"# Oblique asymptotes occur when the degree of the numerator > degree of the denominator. This is not the case here ( both degree 1) Hence there are no oblique asymptotes.
#color(blue)"Intercepts"#
#x=0toy=0/(-15)=0rArr(0,0)#
#y=0to7x=0rArr(0,0)#
graph{(7x)/(-x-15) [-40, 40, -20, 20]}