How do you graph $y=cos^-1x$ over the interval $-1<=x<=1$ ?

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Answer 1 · 2018-08-07T13:22:48

See explanation and graph.

By definition $y = cos^(-1)x in [ 0, pi ]$ and

any cosine value $x in [ - 1, 1 }$ .

The graph that is a half-wave part of the graph of the inverse

$x = cosy$ is confined within the rectangle

#x = - 1, y = 0 , x = 1 and y = pi.

Now see the ( not in uniform scale ) graph,
graph{(y-arccos (x))(y-0.2+0x )(y-3.13 +0.0001y)(x+0.99-0.0001y)(x-1+0.0001y)=0[-1 1 0 3.14]}

See the unrestricted graph $y = (cos)^(-1)x$ , using the inverse $x = cos y$ .
graph{x-cos y = 0[-1 1 -5 5] }

How do you graph y=cos^-1xy=cos^-1x over the interval -1<=x<=1-1<=x<=1?