Question

How do you graph `y=-cot(2x+pi/2)`?

Answer 1

`y= tan(2x)`

Explanation:

`y= - cot (2x+pi/2)`

Here, the angle i.e.`(2x+pi/2)` lies in second quadrant where, cotangent is negative. Also ,
`cot (pi/2 + theta)= -tantheta`

So,

`y= tan(2x)`

graph{y=tan(2x) [-1.92, 1.925, -0.961, 0.959]}