How do you graph y=cot x ? Trigonometry Graphing Trigonometric Functions Graphing Tangent, Cotangent, Secant, and Cosecant 1 Answer sankarankalyanam Jun 28, 2018 As Below. Explanation: y = cot x Standard form is y = A cot (Bx - C) + D A = 1, B = 1, C = 0, D = 0 Amplitude = |A| = color(purple)("NONE for cotangent function" "Period " = pi / |B| = pi / 1 = pi "Phase Shift " = C = 0 "Vertical Shift " = D = 0 graph{cot x [-10, 10, -5, 5]} Answer link Related questions How do you find the asymptotes for the cotangent function? How do you graph tangent and cotangent functions? How do you Sketch the graph of y=-2+cot(1/3)x over the interval [0, 6pi]? How do you graph y=-3tan(x-(pi/4)) over the interval [-pi, 2pi]? How do you sketch a graph of h(x)=5+frac{1}{2} \sec 4x over the interval [0,2pi]? What is the amplitude, period and frequency for the function y=-1+\frac{1}{3} \cot 2x? How do you graph y = 3 sec(2x)? How do you graph y=tan(2x+pi/4)? What is the domain of y = tan(x) + 2? How do you graph csc(x-pi/2)? See all questions in Graphing Tangent, Cotangent, Secant, and Cosecant Impact of this question 4626 views around the world You can reuse this answer Creative Commons License