How do you graph $y=-sec2x$ ?

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Answer 1 · 2018-06-07T01:46:39

As below.

Standard form of Secant function is $color(violet)(y = A sec (Bx - C) + D$

$"Given " y = - sec( 2x)$

$A = -1, B = 2, C = 0, D = 0$

$Amplitude = "None for secant function"$

$"Period " = (2pi) / |B| = (2pi)/ 2 = pi$

$"Phase Shift " = -C / B = 0$

$"Vertical Shift " = D = 0$

graph{-sec (2x) [-10, 10, -5, 5]}

How do you graph y=-sec2xy=-sec2x?