How do you graph #y=-sec2x#?

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Answer 1 · 2018-06-07T01:46:39

As below.

Standard form of Secant function is #color(violet)(y = A sec (Bx - C) + D#

#"Given " y = - sec( 2x)#

#A = -1, B = 2, C = 0, D = 0#

#Amplitude = "None for secant function"#

#"Period " = (2pi) / |B| = (2pi)/ 2 = pi#

#"Phase Shift " = -C / B = 0#

#"Vertical Shift " = D = 0#

graph{-sec (2x) [-10, 10, -5, 5]}