Question

How do you graph `y=-sin(1/10x)`?

Answer 1

Graph inverted on x axis and stretched to a period of `20pi`

Explanation:

`y=-sin(1/10x)`

standard for is:

`y = asin(bx-c)+d`

a = amplitude, `a<0` graph inverts on x axis.

b - horizontal stretch/compression

your c and d are 0

So your graph amplitude `a= -1` so range remains -1 to 1 but the graph is inverted.

your horizontal stretch is `1/10` so the period of your function will be stretched by a factor of 10:

`10*2pi`

graph{-sin(1/10x) [-40, 40, -20, 20]}