How do you graph $y=sin^-1x$ over the interval $-1<=x<=1$ ?

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Answer 1 · 2017-04-13T23:00:47

Here is the graph of $y=sin^(-1)x$ .

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Step 1: Sketch the graph of $y=sin x$ on $[-pi/2,pi/2]$ .

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Step 2: Sketch the line $y=x$ .

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Step 3: Reflect the graph of $y=sin x$ about the line $y=x$ .

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How do you graph y=sin^-1xy=sin^-1x over the interval -1<=x<=1-1<=x<=1?