How do you graph $y=sin(5/3x)$ ?

Question

1661 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-02T10:06:30

As below.

Standard form is $y = A sin (Bx - C) + D$

$Given : " y = sin ((5/3) x$

$'Aplitude " = |A| = 1$

$"Period " = p = (2pi) / |B| = (2pi) / (5/3) = (6pi)/3$

$"Phase Shift " = - C / B = 0$

$"Vertical Shift " = D = 0$

graph{sin ((5/3)x) [-10, 10, -5, 5]}

How do you graph y=sin(5/3x) y=sin(5/3x)?