How do you graph $y = - sin (x + π)$ $y=-sin(x+pi)$ ?

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How do you graph $y = - sin (x + π)$ $y=-sin(x+pi)$ ?

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Answer 1 · 2018-06-02T16:52:04

graph $y = sin (x)$ $y=sin(x)$

Explanation:

we have
$sin (x + π) = sin (x) cos (π) + sin (π) \cdot cos (x) = - sin (x)$ $sin(x+pi)=sin(x)cos(pi)+sin(pi)*cos(x)=-sin(x)$
since
$cos (π) = - 1$ $cos(pi)=-1$ and $sin (π) = 0$ $sin(pi)=0$

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How do you graph $y = - sin (x + π)$ $y=-sin(x+pi)$ ?

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How do you graph $y = - sin (x + π)$ $y=-sin(x+pi)$ ?